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2 years ago

For the animal shelter, Elena Nppurchased

Mathematics

1 answer:

Naddik [55]2 years ago

6 0

Elena's total cost (C) is 5(9.98 + 24.99 + x)

Since each dog leashes cost $9.98, each bag of dog food cost $24.99 and each crate of egg cost $x, hence:

Total cost (C) = 5 * $9.98 + (5 * 24.99) + (5 * x)

C = 5(9.98 + 24.99 + x)

Therefore Elena's total cost (C) is 5(9.98 + 24.99 + x)

Find out more at: brainly.com/question/21105092

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Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

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Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

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Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

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It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

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= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

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