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4 years ago

I need help with this one question. Thanks

Mathematics

1 answer:

Vera_Pavlovna [14]4 years ago

6 0

Answer:

y= -8

Step-by-step explanation:

well since your looking for y put x as zero so its

4x0-5y=40---> -5y=40 so y would be -8

You might be interested in

Ana, Profesora de Psicología de una escuela, planeo realizar un estudio sobre las

alexgriva [62]

Answer:

The answer is below

Step-by-step explanation:

El número de personas que vieron solo A = n (A) = 17

El número de personas que vieron solo B = n (B) = 17

El número de personas que vieron solo C = n (C) = 23

El número de personas que vieron A y B = n (A ∩ B) = 6

El número de personas que vieron A y C = n (A ∩ C) = 8

El número de personas que vieron B y C = n (B ∩ C) = 10

El número de personas que vieron las tres películas = n (A ∩ B ∩ C) = 2

1) Número de estudiantes que han visto dos películas = n (A ∩ B) + n (A ∩ C) + n (B ∩ C) = 6 + 8 + 10 = 24

n (A∩ B '∩ C') = n (A) -n (A ∩ B) -n (A ∩ C) -n (A ∩ B ∩ C) = 17-8-6-2 = 1

n (A'∩ B ∩ C ') = n (B) -n (A ∩ B) -n (B ∩ C) -n (A ∩ B ∩ C) = 17-6-10-2 = 1

n (A'∩ B '∩ C) = norte (C) -n (UNA ∩ C) -n (B ∩ C) -n (UNA ∩ B ∩ C) = 23-8-10-2 = 3

estudiantes que no han visto = 55 - n (A∩ B '∩ C') -n (A'∩ B ∩ C ') - n (A'∩ B ∩ C') - n (A ∩ B) -n ( B ∩ C) -n (UNA ∩ C) -n (A∩ B ∩ C) = 55-1-1-3-6-8-10-2 = 24

número de alumnos que no han visto =

número de estudiantes que vieron solo A = n (A∩ B '∩ C') = 1

8 0

3 years ago

Tyler has to figure out the amount of metal to cover the back of the shelves in Mrs. Edwards room. These are the dimensions. Wha

horsena [70]

The amount of metal he will need to cover the back of the shelves is 180 inches².

The figure above is like a composite figure. Therefore, lets find the area.

<h3>Area of the composite figure</h3>

The area of the figure is the sum of the whole individual 2 dimensional shapes in the composite figure.

Therefore, two rectangles can be drawn from it.

area of rectangle = lw

where

l = length

w = width

Therefore,

area of rectangle 1 = 9 × 8 = 72 inches²

area of rectangle 2 = 6 × 18 = 108 inches²

Total area = 108 + 72 = 180 inches²

Therefore, the amount of metal he will need to cover the back of the shelves is 180 inches².

learn more on area here: brainly.com/question/25849553

4 0

3 years ago

What is a 3, 4, 5 triangle?

Alexandra [31]

Answer:

<em>A special right triangle is a right triangle with some regular feature that makes calculations on the triangle easier, or for which simple formulas exist. For example, a right triangle may have angles that form simple relationships, such as 45°–45°–90°. This is called an "angle-based" right triangle.</em>

Step-by-step explanation:

Hope this helps

Have a nice day :)

5 0

3 years ago

Read 2 more answers

(PLEASE HELP!!!)<br><br> What is g(5) equal to?<br><br> G(t)= -21+3t<br><br> G(5)= ____

Elina [12.6K]

The answer should be g=3t-21/t

6 0

3 years ago

Read 2 more answers

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow

kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

$H_0: \mu = 13252$

At the alternative hypothesis, we test if the mean cost has increased, that is:

$H_1: \mu > 13252$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that $\mu = 13252$

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that $n = 20, X = 15560, s = 3500$

Value of the test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}$

$t = 2.95$

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0

3 years ago