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2 years ago

Help help help help help pleases pelass thank you

Mathematics

1 answer:

Elodia [21]2 years ago

5 0

Answer:

a' (-6,7) b' (-5,3) c'(-2,4)

Step-by-step explanation:

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Pediatricians prescribe 5mL of cough syrup for every 25lb of a child's weight. How many mililiters of cough syrup will the docto

Marianna [84]

Answer:

9 ml

Step-by-step explanation:

The Pediatrician prescribes 5 milliliters of cough syrup for every 25 lb of child weight.

Now, the weight of Jocelyn is 45 lb.

If the rate of prescribing the cough syrup in ml per weight of patients remains constant,

Then we can use the unitary method to get the amount of cough syrup prescribed by the Pediatrician for Jocelyn, and that will be

$\frac{5*45}{25} =9$ ml. (Answer)

3 0

3 years ago

HELP I NEVER LEARND WITH BLOcKS IN ALGEBRA

NISA [10]

Answer:

I need to see the rest of the choices to be able to make a valid decision.

Step-by-step explanation:

I will update this as soon you edit the question

6 0

3 years ago

Read 2 more answers

Triangle ABC is an isosceles triangle. Angles B and C are base angles, with measurements of (11x −10)° and (7x + 10)°, respectiv

Ulleksa [173]

Answer:

m∠A = 90°

Step-by-step explanation:

In isosceles triangle base angles are congruent. That means we can equate measurments of angle B and angle C and solve for x!

m∠B = m∠C

11x - 10 = 7x + 10

4x - 10 = 10

4x = 20

x = 5

Now let's insert x back in the expressions for angles.

m∠B = (11x − 10)° = (11(5) − 10)° = 45°

m∠C = (7x + 10)° = (7(5) + 10)° = 45°

<u>Sum of all angles in the triangle is 180°.</u> Let's make an equation.

m∠A + m∠B + m∠C = 180°

m∠A + 45°+ 45° = 180°

m∠A = 90°

7 0

1 year ago

Solution to square root x-2=x-22

liubo4ka [24]

There are no solutions

6 0

3 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

3 years ago