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quester [9]
3 years ago
13

How do you evaluate the expression-4ac for the following conditions:

Mathematics
2 answers:
Goryan [66]3 years ago
8 0
(a) = 24
(b) = -32
(c) = 20


To evaluate the expression, take what a and c equal and substitute the numbers into the equation and solve.
Aleonysh [2.5K]3 years ago
4 0
A. -4ac
   
    -4(2)(-3)
    multiply
 
    -4(-6)
    multiply, again

    24

b. -4ac

   -4(-4)(-2)
   multiply

   -4(8)
   multiply, again

   -32

c. -4ac

    -4(-1)(5)
    multiply
 
    -4(-5)
    multiply, again

     20
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Eek help? im a bit confused
Ahat [919]

Answer:

3 3/4

Step-by-step explanation:

Each block is worth 0.5 cm (1/2)

One note - NEVER FORGET THE UNITS

L - 5 blocks (5 blocks × 0.5cm = 2.5cm)

W - 2 blocks (2 blocks × 0.5cm = 1cm)

H - 3 blocks (3 blocks × 0.5cm = 1.5cm)

Formula for Volume:

V = L × W × H

V = 2.5cm × 1cm × 1.5cm = 3.75cm (fraction can be 3 3/4)

You're welcome :)

6 0
3 years ago
Read 2 more answers
Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"
Levart [38]

Answer:

\huge\boxed{f(-1) = -7}

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

  • 3(-1)^4 = 3

<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em>-1^4 = -1 (according to my calculator), and 3 \cdot -1 = -3, not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use -2^2 as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than  being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like -1^4. However, since we're substituting in -1, it looks like (-1)^4, so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in -1\cdot-1\cdot-1\cdot-1=1.

Applying this logic to our original term, 3(-1)^4:

  • 3(-1\cdot-1\cdot-1\cdot-1)
  • 3(1)
  • 3

Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: -5x^2

  • -5(-1)^2

Applying the same logic from our first term:

  • -5(-1 \cdot -1)
  • -5(1)
  • -5

Third term: 2x

  • 2(-1) = -2

-3 is just -3, no influence of x.

Combining our terms, we have 3-5-2-3.

This comes out to be -7, hence, the value of f(-1) for our function f(x)=3x^4-5x^2+2x-3 is <u>-7</u>.

Hope this helped!

4 0
4 years ago
Read 2 more answers
Evaluate 51x3 - 21 + 7 when x = -2.<br> DONE
Nana76 [90]

Answer:

-320 i guess

Step-by-step explanation:

51*-2*3-21+7=-320

3 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a
pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

                           ax^2 + bx + c =0  

Where, [ a , b and c are constants ]

- The quadratic formula is given as:

                       

                           x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}

- The given equation is:

                             x^2 + 2x - 120 = 0

Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

                       x = \frac{-2+/-\sqrt{2^2 - 4*1*(-120)} }{2*1}\\\\x = \frac{-2+/-\sqrt{4 + 480} }{2}\\\\x = \frac{-2+/-(22) }{2}\\\\\\x = 10 , -12    

7 0
3 years ago
Help me with the question
Norma-Jean [14]

Answer:

B

Step-by-step explanation:

B is the only one that is actually a point on the graph

3 0
4 years ago
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