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Tcecarenko [31]
3 years ago
7

Segment CD has endpoints at C(0, 3) and D(0, 7). If the segment is dilated by a factor of 3 about point C, what is the length of

the image of segment CD?
Question 7 options:

4


12


16


21
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

The distance is dilated by a factor of 3, the length of the image of segment CD will be 4(3) which is 12 units

Given the coordinate of the segment CD with endpoints at C(0, 3) and D(0, 7) is expressed as:

D=\sqrt{(7-3)^2(0-0)^2}\\D=\sqrt{4^2}\\D = 4 units

If the distance is dilated by a factor of 3, the length of the image of segment CD will be 4(3) which is 12 units

Learn more here: brainly.com/question/22624745

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4 years ago
Solve the equation in the complex number system. x^2-12x+40=0
mylen [45]

solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Step-by-step explanation:

Solve the equation:

x^2-12x+40=0

We can solve using quadratic Formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i

So, solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Keywords: Solving quadratic equation

Learn more about Solving quadratic equation at:

  • brainly.com/question/1414350
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#learnwithBrainly

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