Quadrilateral ABCD is shown. If m angles?

Mathematics

1 answer:

artcher [175]3 years ago

6 0

Answer: m∠BCE = 63°

m∠BAD = 76°

Step-by-step explanation:

Problem 1:

Given

m∠BEC = 90°

m∠EBC = 27°

Total = 117°

Solution:

Subtract 180° - 117° = m∠BCE = 63°

Problem 2:

Given

m∠ADE = 52°

m∠ABE = 52°

Total = 104°

Solution:

Subtract 180° - 104° = m∠BAD = 76°

You might be interested in

dalila says that the data belonging to this box plot down not contain on outlier. do you agree or disagree? explain.

Katen [24]

Yes yes yes yes yes yes

6 0

4 years ago

Read 2 more answers

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US

alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

$\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\$

Calculating the sample size:

$\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2$

$= (\frac{(1.96 \times 0.24 )}{0.10})^2\\\\= 22.13 \approx 23$

In point b:

$\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96 \times 0.24 )}{0.06})^2\\\\= 61.47 \approx 62$

In point c:

$\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$