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3 years ago

HELP PLEASE SOMEONE HELP MEEE ASAPPPP

Mathematics

1 answer:

diamong [38]3 years ago

7 0

Answer:

Step-by-step explanation:

You will multiply 1/3 by 3. This equals 1. 5^1 equals 5.

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The volume of a cube shaped fish tank in Guy Harvey restaurant is 64 cubic feet, the cube-shaped fish tank in the gift shop is 8

vazorg [7]

V=side^3
64cubicfeet=side^3
cube both sides
4ft=side

difference=8ft-4ft=4ft

the difference is 4ft

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a pair of dice is rolled. the observation is the number that comes up on each die. the event, e, is “the sum of the dice is eith

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Answer:

well I'm sure if this is entirely correct but i would say it would be 12

Step-by-step explanation:

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Jessica is collecting aluminum cans during the summer for a recycling project. She collected 120 aluminum cans in June and 150 a

faust18 [17]

Answer:

25%

Step-by-step explanation:

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Bella has a stack of 41 bills (ones, fives, and tens) in an envelope. She has 3 less tens than fives and the quantity of ones do

AleksandrR [38]

Answer:

x+(x-3)+(2*x)=41

Step-by-step explanation:

We know that the other two bills are based of of a constant value for fives. Therefore, the fives can be x. There are 3 less tens than fives, so the number of tens equals x-3. We double the number of fives to get the number of ones, so the number of ones equals 2 times x. When we add all 3 of those together, we get our total number of 41. If you want to solve, you have to solve for x, then you can plug it back into the formula. I hope this helps!

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3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$