Answer:
They are taking 12 2 credit courses
The are taking 4 1 credit courses
Step-by-step explanation:
x = 1 credit courses
y = 2 credit courses
The number of courses is 16
x+y = 16
The number of credits is 28 so multiply the course by the number of credits
1x+2y=28
Subtract the first equation from the second equation
x+2y =28
-x-y=-16
-----------------
y = 12
They are taking 12 2 credit courses
We still need to find the 1 credit courses
x+y = 16
x+12= 16
Subtract 12 from each side
x-12-12 = 16-12
x =4
The are taking 4 1 credit courses
Answer:
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Step-by-step explanation:
Answer:
The domain of the function (cd)(x) will be all real values of x except x = 2.
Step-by-step explanation:
The two functions are
and d(x) = x + 3
So, (cd)(x) = 
Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.
Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)
Q:3
Ans: 10.12 x 10 power -5
Q:4
Ans: 5/8
Q:5
Ans: - x cube and + x square
Answer:
-57/25 or -2 7/25 or - 2.28
Step-by-step explanation: