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2 years ago

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Use the inverse variation equation to fill in the table. P = 8. 31 v volume (liters) pressure (kilopascals) 83. 1 a b 0. 4 415.

5 c a = , b = , c =.

1 answer:

ivanzaharov [21]2 years ago

6 0

Answer:

Explanation:

A=0.1 b=20.775 c= 0.02 on edge :) good luck have a great amazing blessed day!!!

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What is the molarity of a solution that contains 5.80 grams of nickel (ii) nitrate in 500. ml?

Rus_ich [418]

Answer:- 0.0634 M

Explanation:

molarity is defined as the number of moles of solute in 1 L of solution

molar mass of Ni(NO₃)₂ - 182.7 g/mol

number of moles of Ni(NO₃)₂ - 5.80 g/ 182.7 g/mol = 0.0317 mol

number of moles in 500 mL - 0.0317 mol

therefore number of moles in 1000 mL - 0.0317 mol / 500 mL x 1000 mL/L

molarity of the solution is - 0.0634 M

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2 years ago

Ingrid is participating in a relay race. While jogging at 9 km/h, she tosses a relay stick at 16 km/h to her teammate, who is st

Katena32 [7]

Answer:

16 km/h

Explanation:

The relay stick would have the same velocity relative to Ingrid as the velocity she threw it because she threw it while running 9 km/h and the question asks for how fast it is moving RELATIVE to Ingrid, who also started off moving at 9 km/h.

Sorry if explanation is bad, this one was a bit of head scratcher for me to wrap my head around ig.

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2 years ago

When heating a substance, a phase change will start to occur when the kinetic energy of the particles is _____________ the attra

Paraphin [41]

Great enough to overcome

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2 years ago

Which of the following is typically not found on a prescription label:.

rewona [7]

Answer:

d

Explanation:

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3 years ago

Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll

Andrew [12]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed <em>95% confidence interval</em>, with 49 - 1 = <em>48 df</em>, is t = 2.0106.

Hence:

$\overline{x} - t\frac{s}{\sqrt{n}} = 12.2 - 2.0106\frac{1.6}{\sqrt{49}} = 11.7$

$\overline{x} + t\frac{s}{\sqrt{n}} = 12.2 + 2.0106\frac{1.6}{\sqrt{49}} = 12.7$

The 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

More can be learned about the t-distribution at brainly.com/question/16162795

4 0

2 years ago