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m_a_m_a [10]
2 years ago
10

Cooper earned $214.50 at his job when he worked for 13 hours. How much money did he earn each hour?

Mathematics
1 answer:
Lerok [7]2 years ago
8 0

Answer:

$16.50

Step-by-step explanation:

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Draw an area model to solve 549÷ 3
Allisa [31]

Answer:

183

Step-by-step explanation:

i cant draw an actual model but 549/3 = 183

7 0
3 years ago
PLEASE HELP!!!<br><br>Can sometime help me solve this?
damaskus [11]
Hope you understand. tell me if u need help

3 0
3 years ago
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Find the volume of a rectangular prism with a length of 9 cm, a height of 13 cm, and a width of 7 cm.
Sati [7]

Answer:

819 cm³

Step-by-step explanation:

V=L·H·W

V=9·13·7

V=819 cm³

4 0
2 years ago
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What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
3 years ago
!!!!!!!!!!!!!!!!!! help
Triss [41]

Answer:

option 1

Step-by-step explanation:

It's given in the question that

a (first term of an A.P.) = 14

d (common difference between terms of A.P.) = -3

So,

2nd term will be = a + d = 14 + (-3) = 11

3rd term = a + 2d = 14 + 2×(-3) = 8

4th term = a + 3d = 14 + 3×(-3) = 5

All these terms are matching with option 1. So, option 1 is the correct option

3 0
3 years ago
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