The expression relating the distance and the time is:
velocity = distance / time
We are given the velocity as 12 km/h
Part a:
for t = 3.5 hours
velocity = distance / time
distance = velocity x time
distance = 12 x 3.5 = 42 km
Part b:
for s = 30 km
velocity = distance / time
time = distance / velocity
time = 30 / 12 = 2.5 hours
2x^2 - 5x + 12 = 0
Factoring out the leading coefficient:
2(x^2 - 5/2 x) + 12 = 0
Completing the square:
2[(x - 5/4)^2 - 25/16] + 12 = 0
2(x - 5/4)^2 - 25/8 + 12 = 0
2(x - 5/4)^2 + 71/8 = 0
q = 71/8
Normal or natural variations in the quality of production output that are due purely to chance are common causes.
According to the statement
we have to tell about the that cause which effect the quality and production output in the normal and natural variation.
So, For this purpose, we know that the
Common cause variation is present when the control chart of a process measure shows a random pattern of variation with all points within the control limits. When a control chart shows common cause variation, a process measure is said to be in statistical control or stable.
And due to this cause there is a lot of effect on the natural variations in the quality of production output.
So, Normal or natural variations in the quality of production output that are due purely to chance are common causes.
Learn more about common cause variation here
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Answer:
0.072
Step-by-step explanation:
3 1/3. Because, 60 divided by 25 2.4. 8 divided by 2.4 is 3.3 which is equal to 3 1/3.
