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3 years ago

1. What is the domainof the relation {(3,4), (1,2), (-3, -5), (0, -8)}?

Mathematics

1 answer:

Marizza181 [45]3 years ago

3 0

Wouldn’t it be D. since the domain is x. (x,y)

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I need to solve 6 2/3-21/6

lora16 [44]

Step-by-step explanation:

62/3-21

62/18=0.290

290/6

Divide it

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3 years ago

Graph a right triangle with the two points 4,5 and -4,8

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Please write points using parentheses: (4, 5) and (-4, 8}.

(4, 5) is in the 1st quadrant and (-4, 8} is in the 2nd. Reversing the order of these two points yields (-4, 8) and (4, 5). From this we can see that while moving from (-4, 8) to (4, 5) involves following a line with negative slope (because the y-coordinate decreases from 8 to 5 as the x-coordinate increases from -4 to +4). This sloping line is the hypotenuse of a right triangle. Draw a vertical line segment through (-4, 8) and a horizontal line segment through (4, 5). This hypotenuse, the vertical line segment and the horizontal line segment are the boundaries of the desired right triangle.

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4 years ago

The top option, "meat lovers", received 12 votes. Was this majority of the votes?

ICE Princess25 [194]

Answer:

Step-by-step explanation:

if the number of votes is 25, 12 is not majority

but if the number is 23 then 12 is majority

6 0

3 years ago

64.3- 3 x 23 - 2 is what.

Lena [83]

Answer: -6.7

Step-by-step explanation:

64.3−(3)(23)−2

=−6.7

3 0

3 years ago

Read 2 more answers

What is a radius of a circle given by the equation x²-2x+8y-47=0

Zolol [24]

First, we are going to rewrite it as a parabola equation.
Rewrite.
$8y=-x^2+2x+47$
Divide by 8.
$y=-\frac{x^2}{8}+\frac{x}{4}+\frac{47}{8}$
Factor out coefficient.
$y=-\frac{1}{8}\left(x^2-2x\right)+\frac{47}{8}$
Then, we are going to convert x into square form.
$y=-\frac{1}{8}\left(x^2-2x+1\right)+\frac{1}{8}\cdot \:1+\frac{47}{8}$
Convert the whole expression into square form.
$y=-\frac{1}{8}\left(x-1\right)^2+\frac{1}{8}\cdot \:1+\frac{47}{8}$
Simplify.
$y=-\frac{1}{8}\left(x-1\right)^2+6$
Subtract 6 from both sides.
$y-6=-\frac{1}{8}\left(x-1\right)^2$
Divide by coefficient.
$-8\left(y-6\right)=\left(x-1\right)^2$
Rewrite in standard form.
$4\left(-2\right)\left(y-6\right)=\left(x-1\right)^2$

The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive.
Have a nice day! :)

7 0

3 years ago

Read 2 more answers