Haley bought 2.5 pounds of almonds for $16.20. How much did she pay per pound for the almonds?

Travis has a budget of $300 that he can spend on perennial flowers and at least 6 annual flowers. Perennial flowers are 18 dolla

boyakko [2]

Answer:

18x + 15y ≤ 300
x ≥ 0; y ≥ 6

Step-by-step explanation:

Variables are defined in the problem statement.

18x +15y ≤ 300 . . . . total budget

y ≥ 6 . . . . . . . . . . . . minimum number of annuals

x ≥ 0 . . . . . number of perennials cannot be negative

This system of inequalities describes the situation.

6 0

3 years ago

The slope of EF¯¯¯¯ is −5/2 .

stellarik [79]

Answer:

LM and NP

Step-by-step explanation:

LM= 2/5

NP=2/5

GH= -5/2

JK= =5/2

4 0

3 years ago

Can anybody help with my work

quester [9]

I think the answer is 20.34 I might be wrong someone else could check

5 0

2 years ago

Read 2 more answers

Tia measured the daily high temperature in Kats, Colorado for each of the 30 days in April. She then created both a dot plot and

lara31 [8.8K]

*see attachment below showing the dot plot and box plot created by Tia

Answer:

Dot plot

Step-by-step explanation:

In a dot plot, the temperature of a day is represented by 1 dot. There are 30 dots on the box plot shown in the attachment that was made by Tia.

This dot plot display makes it easier to find how many days had a temperature that is higher than 15°.

Thus, from the dot plot, we have:

2 dots representing 2 days having a temperature of 16°C each

2 days also have daily temperature of 17°C

2 days have temperature of 18°C as well, and

1 day has temperature of 19° C.

Therefore, the number of days that had a temperature above 15°C is 7 days.

3 0

3 years ago

Read 2 more answers

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

3 years ago