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Nitella [24]
3 years ago
5

Find the Area and

Mathematics
1 answer:
Igoryamba3 years ago
6 0

Answer:

you need to show the circumference, instead I cant help

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LC)Which of the following algebraic expressions can be used to express the statement "three less than a squared?"
adoni [48]

Answer:

A

Step-by-step explanation:

mark me brainliest pls

3 0
3 years ago
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Given that f(x) = x2 − 3x + 3 and g(x) = , solve for f(g(x)) when x = 5. −3 1 7 13
Temka [501]
f(x) = x^{2} - 3x + 3 \\
g(x) =  \frac{x - 1}{4} \\
g(5) = \frac{(5) - 1}{4} = 1 \\
f(1) = (1)^{2} - 3(1) + 3 = 1 \\
Therfore, f(g(5)) = 1
4 0
3 years ago
If f(x)=x+4/x , g(x)= x-2, and h(x) =4x-1, what is f(h(g(x)
xxMikexx [17]

Answer:

(16x² - 72x + 85) / (4x-9)

Step-by-step explanation:

first put g(x) into h(x)

h(g(x)) = 4(x-2) - 1 = 4x - 8 - 1 = 4x - 9, then

f(h(g(x))) = (4x - 9) + (4/4x-9) = ((4x-9)(4x-9) + 4)/(4x-9) =

(16x² - 72x + 81 + 4)/(4x-9) = (16x² - 72x + 85)/(4x-9)

If you are missing parentheses around (x+4)/x, then the answer would be different.

3 0
3 years ago
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I really need help on this question!!!
Cloud [144]

Answer: 45 mph

Step-by-step explanation:

We know that Rob was driving 63 mph which is 18 miles faster than pigeons, therefore you subtract to get the answer.

63-18=45

6 0
4 years ago
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Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T
Katyanochek1 [597]

Answer:

m∠QRT = 90°

m∠QRT = m∠SRT

Step-by-step explanation:

Triangle QST is isosceles with QT ≅ ST. In isoscels triangle QST, angles STR and RTQ are congruent.

RT is angle T bisector, so angles QTR and STR are congruent.

Consider two triangles QTR and STR. In these triangles:

  • TR ≅ TR (reflexive property);
  • ∠QTR ≅ ∠STR (given);
  • QT ≅ ST (given).

By SAS postulate, these two triangles are congruent. Two congruent triangles have congruent corresponding sides, so

  • QR ≅ SR
  • ∠QRT ≅ ∠SRT

Angles QRT and SRT are supplementary (add up to 180°). Since these two angles are congruent, they have the same measure equal to \frac{1}{2}\cdot 180^{\circ}=90^{\circ}

So, true options are

m∠QRT = 90°

m∠QRT = m∠SRT

7 0
4 years ago
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