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Vilka [71]
2 years ago
9

10x^3/5x^2 2/x. 2x 2 x/2

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0
-5x•(2x^2+x+3) is the answer
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What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?
olga2289 [7]

Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

<u>Find the equation of the line with mCD and the point (3,0)</u>

we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

4 0
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Substitute the values given.
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The figure shows the location of 3 points around a lake. The length of the lake, BC, is also shown.
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Answer:

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Step-by-step explanation:

Pythagorean theorem is used

We will call AB x

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<u>x = 5.26</u>

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The maximum number of students in a classroom
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10 students can join the class without exceeding the maximum
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