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Vilka [71]
3 years ago
9

10x^3/5x^2 2/x. 2x 2 x/2

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0
-5x•(2x^2+x+3) is the answer
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For the end-of-year party, Mt.Rise Middle School ordered 112 pizzas. There were eight fewer veggie pizzas than there were pepper
rodikova [14]
Let the number of pepperoni pizzas be x
pepperoni = x
veggie = x - 8    [<span>There were eight fewer veggie than pepperoni]
</span>combo = 3x       [T<span>here were three times as many combo as pepperoni]
</span>
Given that the total Pizza: 112
x + x - 8 + 3x = 112
5x - 8 = 112
5x = 112 + 8
5x = 120
x = 24

x= 24
x - 8 = 16
3x = 72

So there were 24 pepperoni pizza, 16 veggie pizza and 72 combo pizza

5 0
3 years ago
A number increased by fifteen is nineteen. A number increased by fifteen is nineteen.
elixir [45]

Answer:

the number is 4

Step-by-step explanation:

we can write this as

x + 15 = 19

now we transpose

x= 19-15

x= 4

5 0
3 years ago
F(x)= x squared + 6x + 8
defon

Answer: (x+4) (x+2)

Step-by-step explanation:

x^2 + 2x + 4x +8

4 0
3 years ago
8x-18=30 math homework I need help
horsena [70]
Ok i will give you a hint ok look subtract 18-30 then you will get yhe answef for 8× ok try it
7 0
3 years ago
Read 2 more answers
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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