All categories

3 years ago

720x + 10 = 2170 What is x?

Mathematics

2 answers:

AysviL [449]3 years ago

3 0

Answer:

x = 3

Step-by-step explanation:

720x + 10 = 2170

=> 720x = 2160

=> x = 3

Hoped this helped.

ioda3 years ago

3 0

Answer:

x = 3

Step-by-step explanation:

First subtract 10 from 2,170 to get 2,160.

Next isolate the x variable by dividing 720 on both sides to get x = 3.

Hope this helps you :)

You might be interested in

How many fluid ounces are in 3 quarts?

puteri [66]

There are 96 fluid ounces in 3 quarts

7 0

3 years ago

Read 2 more answers

How do I solve the equation 2x-5x+6.3=-14.4

Serga [27]

-3x+6.3=-14.4
-6.3=-6.3
-3x=-20.7
-3 -3
x=6.9

7 0

3 years ago

Please help!!!!!!!!!

LenKa [72]

The only true statement is the first option A. There are no maximums and the other two statements are also false.

8 0

3 years ago

What is the area of Figure ABCD? answer choices are A:54 B:60 C:66 D:72

FinnZ [79.3K]

C is the answer or 66

7 0

3 years ago

If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:

Liula [17]

Answer:

(a) The mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(d) The mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable X follows a Binomial distribution with parameters n and p.

The mean, variance and standard deviation of X are:

$\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}$

(a)

For n = 4 and p = 0.40 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98$

Thus, the mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b)

For n = 4 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80$

Thus, the mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(c)

For n = 3 and p = 0.50 compute the mean, variance and standard deviation of X as follows:

$\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87$

Thus, the mean, variance and standard deviation of X are 1.50, 0.75 and 0.87 respectively.

(d)

For n = 5 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89$

Thus, the mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

6 0

3 years ago