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3 years ago

I need help with math!!!!

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

id say caculate :) 649.99 and 20% and the same for the others

Step-by-step explanation:

You might be interested in

Solve 29 < m^2+ 9/2<br> < 45

german

Answer:29m^2+

405/2

Step-by-step explanation:

4 0

3 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

4 years ago

Read 2 more answers

How can we solve fractions

tatuchka [14]

Answer:You can solve fraction by taking LCM

Step-by-step explanation:

For example: (1/4)+(1/2)is the question

Answer:LCM=4

(1/4)+(1*2/2*2)

(1/4)+(2/4)

(1+2/4)

(3/4)

Here is the answer

8 0

3 years ago

Rebecca has a credit line of $6,500. She had a previous balance of $398.64 and made a payment of $250. The total of her purchase

valentina_108 [34]

Answer:

$5093.37

Step-by-step explanation:

To get Rebecca's available credit we need to take all of her payments and purchases and previous balance.

Previous balance = $398.64

Purchases = $1,257.99

Payment = $250

Credit Line = $6,500

Now first we add together her purchases and previous balance.

398.64 + 1,257.99

This will give us:

$1,656.63 Total deductions.

Now we subtract that to her credit line.

$6500.00 - $1656.63

$4843.37

Now we take her payment and add it to her credit line.

$4843.37 + $250

$5093.37

So Rebecca's available credit is $5093.37.

4 0

3 years ago

4/9 kilograms of baking soda cost $1.50. How much does 1 kilogram of baking soda cost?

mrs_skeptik [129]

Answer:

Step-by-step explanation:

divide 1.5 by 4 to get 1/9 of the cost, and then multiply that by 9 to get the cost of one kilo.

or 3.375, round it for money purposes

$3.38

8 0

3 years ago