Answer:
False
Step-by-step explanation:
Lets call the three prime divisors of n p, q, and r, being r the largest, we know:

Now, if

then

So:

Also, for every natural greater than one, we know:
![\sqrt[3]{n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3C%5Csqrt%7Bn%7D)
so
![\sqrt[3]{n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3C%5Csqrt%7Bn%7D%20%3C%20r)
from which:
![\sqrt[3]{n} < r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%20%3C%20r)
So, we see, this means the preposition is false, we can find a particular counterexample:
q=2
p=3
p*q = 6
We need to choose a prime greater than 6
r=7
n= 2 * 3 *7 = 42
![\sqrt[3]{42} = 3.4760 < 7](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B42%7D%20%3D%203.4760%20%3C%207)
P = 300 $; r = 0.06; t = 20; n = 1
A = P ( 1 + r/n)^n*t
= 300 ( 1 + 0.06) ²⁰
= 300 ( 1.06) ²⁰
= 962.14
First angle= x+10
Second angle = x
Third angle = x+x+10 or 2x+10
X+10+x+2x +10=180
4x+20=180
Subtract 20 from both sides
4x=160
Divide both sides by 4
X=40
First angle =50
Second angle=40
Third angle =90
Move the decimal twice to the right to get a decimal (it should start behind the 2 and end up in front of the 7)
For a fraction just put it over 100 72/100
The second option , s = 74 - 33