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belka [17]
2 years ago
5

The sides of a triangle have lengths 3, 25, and 27. What kind of triangle is it ?

Mathematics
1 answer:
Andrew [12]2 years ago
3 0

Answer:

Step-by-step explanation:

it's obtuse the sides are to wide

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What are the 6 trigonometry functions
EastWind [94]

Sine, Cosine, Tangent, Cosecant (opposite of Sine), Secant (opposite of Cosine), and Cotangent (opposite of Tangent)

3 0
4 years ago
A computed measure of how much scores vary around the mean score
Paladinen [302]
That's called <span>standard deviation.

Hope this helps !

Photon</span>
5 0
3 years ago
Ann has 30% less money than Mary, and Jessica has 70% more than Mary. If the 3 of them have a (added up) total of $102, how much
Roman55 [17]
Let x be the amount of Ann money, y be Jessica's money and z Mary money. 
30% of z equates 0.3*z. 
Ann has 30% less than z so: x = z - 0.3z = 0.7z.
70% of z equates 0.7z. 
"Jessica has 70% more than Mary " we deduce the equation: y =z+0.7z= 1.7z.
Signe the total is $102, we deduce the equation x+y+z = 102. 
x=0.7z and y=1.7z then 0.7z+1.7z+z=102, therefore 3.4z=102 then 
z =102/3.4 = $30.
x=0.7*30= 21 and y=1.7*30=51.

Ann has $21, Mary has $30 and Jessica has $51.
  
3 0
4 years ago
Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
the circumference of a circle is about 25.3 in find the area of the circle using 3.14 as an approximation for pie.Round your ans
sertanlavr [38]
<span>50.962 is answer m8t</span>
3 0
3 years ago
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