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DaniilM [7]
3 years ago
15

5[x-(4x-5)]=3-8x Solving for x

Mathematics
1 answer:
stiv31 [10]3 years ago
7 0
5(x-4x+5)=3-8x
5x-20x+25=3-8x
-15x+25=3-8x
-7x+25=3
-7x=-22
x= 22/7

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A company has 2 machines that manufacture widgets. An older machine manufactures 25% defective widgets, while the new machine ma
Bingel [31]

Answer:

73.90%

Step-by-step explanation:

Let Event D=Defective,  D' = Non Defective

Let Event N=New Machine, N' = Old Machine

From the given information:

P(D|N')=0.25\\P(D|N)=0.09\\P(N)=0.7\\P(N')=0.3

We are required to calculate the probability that a widget was manufactured by the new machine given that it is non defective.  

i.e. P(N|D')

P(D'|N')=1-P(D|N')=1-0.25=0.75\\P(D'|N)=1-P(D|N)=1-0.09=0.91

Using Baye's Law of conditional Probability

P(N|D')=\dfrac{P(D'|N)P(N)}{P(D'|N)P(N)+P(D'|N')P(N')} \\=\dfrac{0.91*0.7}{0.91*0.7+0.75*0.3}\\ =0.73897\\\approx 0.7390

Therefore given that a selected widget is non-defective, the probability that it was manufactured by the new machine is 73.9%.

5 0
3 years ago
X^8y-26/x^14y^-5*x^-39y^-21
Mice21 [21]

Answer: The exponent of x = -45

The exponent of y = -42

Step-by-step explanation:

Since, the exponent of a variable is the power of the variable.

Given expression is,

\frac{x^8y^{-26} }{x^{14}y^{-5}} \times x^{-39}y^{-21}

\frac{x^8y^{-26} x^{-39}y^{-21} }{x^{14}y^{-5}}

x^8y^{-26} x^{-39}y^{-21} x^{-14}y^{5}   (\text{Because, }\frac{1}{a^m} = a^{-m})

x^{8-39-14}y^{-26-21+5}    (\text{ Because, } a^m\times a^n = a^{m+n})

x^{-45}y^{-42}

Since the power of x = -45

⇒ The exponent of x = -45

Similarly, the exponent of y = -42.


5 0
3 years ago
Need help with this!!!
Scorpion4ik [409]

Answer:

I say the fourth one just because

7 0
4 years ago
Solve for x if sqrt (3x-8) + 1 = sqrt (x+5)
In-s [12.5K]

The solution of x in the given expression \mathbf{\sqrt{(3x-8)}+1 = \sqrt{(x+5)}} is 4. However, if it is \mathbf{\sqrt{(3x-8)+1} = \sqrt{(x+5)}}, it is 6.

<h3>What is the solution to algebraic expression?</h3>

The solution to the given algebra expression involving surds can be seen in the steps below.

Given that:

\mathbf{\sqrt{(3x-8)}+1 = \sqrt{(x+5)}}

Remove the square roots, we have:

12x - 32 = 4x² - 48x + 144

Solving the quadratic equation at the RHS and equating it to LHS, we have:

x = 11, x = 4

Verifying the solutions by replacing the value of x with the given equation:

  • x = 11 False
  • x = 4 True

Therefore, we can conclude that the value of x = 4

NOTE:

Given that:

\mathbf{\sqrt{(3x-8+1)} = \sqrt{(x+5)}}

Square both sides

3x - 7 = x +5

Solve for x

3x - x = 5 + 7

2x = 12

x = 6

Learn more about solving to algebraic expressions here:

brainly.com/question/4344214

#SPJ1

5 0
2 years ago
What is the equation of the function
dem82 [27]

Answer:

a is the same answer to this topic is the best way

5 0
3 years ago
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