Question

Answer answer answer plzz

Answer 1

Answer:  g > 6

The graph is below

The graph has an open hole at 6; shading to the right

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Explanation:

I'm assuming the variable g is not in the denominator.

To solve for g, we'll first multiply both sides by 3

$-\frac{2}{3}g < -4\\\\3*\left(-\frac{2}{3}g\right) < 3(-4)\\\\-2g < -12$

Then divide both sides by -2 to fully isolate g. Dividing both sides by a negative value flips the inequality sign.

$-2g < -12\\\\\frac{-2g}{-2} > \frac{-12}{-2}\\\\g > 6$

The solution for g is any number larger than 6.

The graph will have an open hole at 6 and shading to the right. See below.