Answer:
1st box: Asso. prop= m+(4+x)
2nd box: Comm. Prop= m+4=4+m
3rd box: iden. prop= m+0=m
4th box: Zero prop: m x 0=0
#3
2 and three are supplementary angles .
#4.
The answer is opposite angles .
#5
Bisected angles are equal
![\\ \sf\longmapsto 5x=3x+10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%205x%3D3x%2B10)
![\\ \sf\longmapsto 5x-3x=10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%205x-3x%3D10)
![\\ \sf\longmapsto 2x=10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%202x%3D10)
![\\ \sf\longmapsto x=\dfrac{10}{2}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20x%3D%5Cdfrac%7B10%7D%7B2%7D)
![\\ \sf\longmapsto x=5](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20x%3D5)
Now
m<ABC
![\\ \sf\longmapsto 5x+3x+10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%205x%2B3x%2B10)
![\\ \sf\longmapsto 8x+10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%208x%2B10)
![\\ \sf\longmapsto 8(5)+10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%208%285%29%2B10)
![\\ \sf\longmapsto 40+10](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2040%2B10)
![\\ \sf\longmapsto 50](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2050)
The answer is B. 8/9 •4/3
C because there is 180 degrees in a triangle. 147+17=164 and 180-164 is 16
Answer:
A: 6 boxes right, 9 boxes down, 9 boxes left, connect back to start.
B: 3 boxes right, 9 boxes up, (diagonal 6 right, 12 down), 9 boxes up, 6 boxes right.
C: 1 box right, 2 boxes down, 1.5 boxes right, 1 box up, .5 box right, 2.5 boxes down, 3 boxes left, 3.5 boxes up to connect.
D: (diagonal 1 up, 1 right), 1 box right, (diagonal 1 down, 1 right), 1 box down, (diagonal 3 down, 3 left), 3 boxes left
Step-by-step explanation: