Answer:
I may not be correct, depending on what you were taught, but it would be...
17/30
Step-by-step explanation:
(2/5×6/6)+(1/6×5/5)
12/30 + 5/30
17/30
keep in mind you don't add the denominators at all ( the numbers at the bottom half of the fraction)
Answer: 7
Step-by-step explanation:
As tangents drawn from a common external point to a circle are congruent,
- 8x - 7 = 6x + 7
- 2x - 7 = 7 [subtract 2x from both sides]
- 2x = 14 [add 7 to both sides]
- x = 7 [divide both sides by 2]
Answer:
first off, this may be completely wrong, but I did try my best. You need to clarify what this is for so I went with the easiest route, solving for variables.
P=0
X= - 3/4
Step-by-step explanation:
P(-2)=-3+4x
Solving for X
-2P=-3+4x
-2(0)=-3+4x
-3=4x
- 3/4=X
Solving For P
P(-2)=3+4(- 3/4)
P(-2)3-3
P=0
Keep the bases of 6 and add exponents: 
Keep the bases of 11 and add exponents: 
So its C.
hope that helps :)
Since 5 winning numbers are draw and there are exactly 2 winning numbers, the other 3 numbers chosen have to be incorrect.
The 2 numbers picked right, there are 5C2=10 different possibilities.
The other 3 numbers are just picked from the rest of the 32 numbers. Getting there are 32C3=4960 different possibilities.
For each set of 2 correct winning numbers, you could have the 4960 different losing numbers to match up to make a unique set. This meant that there are 4690*10=46900 different total possibilities.
Now the total different outcomes of how you can choose the numbers are 37C5=435897 outcomes.
Now the way to find probabilities is want/total
The want is 46900 and the total is 435897
Doing the division you get the number rounded to the nearest thousandths as 0.107 or in percent form as
10.759% chance of picking exactly 2 winning numbers.
This seems like a competition problem of some sort therefore I assume that you already know what combinations in form nCk and permutation in form nPk means.
