Answer:
1/3
Step-by-step explanation:
Parallel lines are in the same plane, never intersect, and have the same slope.
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
The value of the expression for the given values of a and b is -1
<h3>Evaluating an expression</h3>
From the question, we are to evaluate the given expression for the given values of a, b, and c
The given expression is
a + b
The given values are
a = 4,
b = -5,
and
c = -8
To evaluate the given expression for the given values of a and b, we will put the values of a and b into the expression,
That is,
a + b becomes
4 + -5
= 4 -5
= -1
Hence, the value of the expression for the given values of a and b is -1
Learn more on Evaluating an expression here: brainly.com/question/17425636
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