Answer:log1.39*10^12=12.14
Step-by-step explanation:
Hi,
Let's simplify this equation step-by-step.
7−2(5−2x)−10x+25−4x−3
Distribute:
=7+(−2)(5)+(−2)(−2x)+−10x+25+−4x+−3
=7+−10+4x+−10x+25+−4x+−3
Combine Like Terms:
=7+−10+4x+−10x+25+−4x+−3
=(4x+−10x+−4x)+(7+−10+25+−3)
=−10x+19
Answer:
=−10x+19
Have a great day!
Answer:
Bet
Step-by-step explanation:
It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
