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nirvana33 [79]
3 years ago
13

Help me please i beg you

Mathematics
1 answer:
k0ka [10]3 years ago
8 0
ANSWER: Acute and obtuse angle
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Find the average value of the function f(t)=(t-2)^2 on [0,6]
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2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

                      f(b) - f(a)

ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

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For a = 0, we get:

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Plugging these results into the ave. value function shown above, we get:

                      16 - 4

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                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


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