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Charra [1.4K]
2 years ago
5

What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9?

Mathematics
2 answers:
Blizzard [7]2 years ago
8 0
Vertex: (-1,7)
Focus: (-1, 57 over 8)
Axis of Symmetry(AOS): x=-1
Directories: y= 55 over 8
X , Y
-3 , 15
-2 , 9
-1 , 7
0 , 9
1 , 5
Vlada [557]2 years ago
5 0
Your equation f(x)=2x^2+4x+9 is in the form y=ax^2+bx+c
The vertex only relies on "a" and "b" though, so that +9 doesn't really matter in this case.  The vertex of a parabola is located where 
x=\frac{-b}{2a}=\frac{-4}{2(2)}=-1
So your x-coordinate is -1.  You need to find f(-1) to find your y-coordinate, and then you list it in the form (-1, y).
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To maximize Area A(y)

A'(y)= 0

2y/4\pi + 2(y-2)/16 =0

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x=2/\pi+4

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4 0
1 year ago
Y = (4x^3 +8)^1/3/(x+2)^5
WITCHER [35]

Answer:

y=4

Step-by-step explanation:

7 0
3 years ago
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I really hope this helps :D:D:D!!!!

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The difference of twice a number and 3 is -21 translated
Westkost [7]

Answer:

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3 years ago
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