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3 years ago

Find the coordinates of the midpoint ab a(6,4) and b(2,-6)

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

`let a(6,4) be x1, y1

b (2, -6) be x2,y2

coordinates of midpoint = { (x1+x2/2), (y1 +y2/2)

= (4, -1)

Step-by-step explanation:

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Hey pls help worth 30 points

GrogVix [38]

Step 1: Find the slope:

$m = \dfrac{y_2-y_1}{x_2-x_1} = \dfrac{10-6}{6-5} = \dfrac{4}{1} = 4$

Step 2: Set up your equation $y-y_1=m(x-x_1)$ using one of the points.

Using (5,6) we have $y-6 = 4(x-5)$ .

Using (6,10) we have $y-10 = 4(x-6)$

Both of those equations would be correct.

5 0

2 years ago

Read 2 more answers

Solve st + 3t = 6 for s

vaieri [72.5K]

st + 3t = 6 for s

Subtract 3t to both sides

st + 3t - 3t = 6 - 3t

Simplify

st = 6 - 3t

Divide both sides by t

st/t = (6-3t)/3

simplify

s = 6/3 - 3t/3

s = 2 - t

6 0

3 years ago

Find a round to the nearest tenth a 150 12 10cm c a=?cm

Kryger [21]

Answer:

<h3> $Using~ the ~ law~ of ~sinse:-$ </h3><h3> $\frac{a}{SinA} =\frac{b}{SinB}$ </h3>

$\frac{a}{Sin150}$ $=\frac{b}{SinB}$

$a=\frac{10~sin~150}{Sin~12}$

$a=[24] ~cm$

<h3><u>-----------------------</u></h3><h3><u>hope it helps..</u></h3><h3><u>have a great day!!</u></h3>

7 0

2 years ago

A cylinder has a volume of 625 cubic feet and has a radius of 9 feet which of the following equations could be used to find h th

kifflom [539]

Answer:

Divide

Step-by-step explanation:

im think you have to divide to find the height of the cylinder.

625 divide 9 = 69.44

3 0

2 years ago

A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

Shalnov [3]

Answer:

We conclude that the true average percentage of organic matter in such soil is different from 3%.

Step-by-step explanation:

We are given that the values of the sample mean and sample standard deviation are 2.481 and 1.616, respectively.

Suppose we know the population distribution is normal, we have to test the hypothesis that does this data suggest that the true average percentage of organic matter in such soil is something other than 3%.

<em>Let </em> $\mu$ <em> = true average percentage of organic matter in such soil</em>

SO, <u>Null Hypothesis</u>, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is equal to 3%}

<u>Alternate Hypothesis</u>, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is different than 3%}

The test statistics that will be used here is <u>One-sample t test statistics</u> because we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, <u><em>test statistics</em></u> = $\frac{0.02481-0.03}{{\frac{0.01616}{\sqrt{30} } } }$ ~ $t_2_9$

= -1.759

<u></u>

<u>Now, P-value of the test statistics is given by;</u>

P-value = P( $t_2_9$ > -1.759) = <u>0.046</u> or 4.6%

If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.

If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.046 which is clearly smaller than the level of significance of 0.05 (for two-tailed test), so we will reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the true average percentage of organic matter in such soil is different from 3%.

3 0

3 years ago