Answer:
-x^4-5x^3+2x²+ 10x = (x+5)(2x-x³)
Step by Step explanation
Naming the coefficient of x² as "a" and the independent temine of the first parenthesis as "b", we got:
-x^4-5x^3+ ax^2 +10x=(x+b)(2x-x^3)
- x⁴-5x^3+ ax^2 +10x = 2x²- x⁴+2bx-bx³
-5x^3+ ax^2 +10x = -bx³+2x²+2bx
( Matching the exponents)
For x: 2b= 10; b=10/2.
b=5
For x²: a=2
For x³: -b=-5
b=5
Answer:
so 2/3X 3/5 + 3
10 + 9 / 15 by LCM method
so 19/15 + 3 = 19/15 + 45/15 = 64/15
hope it helps
Step-by-step explanation:
Vertex: (-5,-2); parabola opens up;
General form of the equation for a vertical parabola opening up is:
y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:
y+2 = a(x+5)^2. We need to find the value of the coefficient a.
From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).
subst. these values into y+2 = a(x+5)^2, we get:
10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or 1 = a(169/16).
Solving for a: a = 16/169 = 0.09, or approx 16/160, or 1/10. Unfortunately, this is not close to any of the four answer choices.
I thought it best to try again, and fortunately my second try was correct:
10+2 = a(13/4)^2, or (169/16)a. Thus, 12 = a(169/16)
12
Solving for a: a = ------------- = 1.14. The answer choice closest to this is 1.
169/16
Answer A is correct.
