Question

Find the product. 3y 2 z(2y 2 z + 4yz - y + z)

Answer 1

Answer: 48(y*z)^2 - 6z*y^2 - 6y*z^2

Step-by-step explanation: We want to find the product:

3y*2z*(2y*2z + 4yz - y - z)

First, distribute the product:

3y*2z*2y*2z + 3y*2z*4yz -*3y*2z*y - 3y*2z*z

now, let's simplify the equation:

(3*2*2*2)(y*z)^2 + (3*2*4)(y*z)^2 - (3*2)z*y^2 - (3*2)y*z^2

24(y*z)^2 + 24(y*z)^2 - 6z*y^2 - 6y*z^2

48(y*z)^2 - 6z*y^2 - 6y*z^2

If the equation you want to distribute is:

(3y^2z)*(2y^2z + 4yz - y - z)

the distribution is:

(3y^2z)´*(2y^2z) + (3y^2z)*4yz -(3y^2z)*y - (3y^2z)*z

6y^4z + 12y^(2z + 1)*z - 3y^(3z + 1) - (3y^2z)*z

Answer 2

3y^2z*(2y^4yz-y+z)

=6y^(4z)+12y^(1+2z)z-3y^(1+2z)+3zy^(2z)