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k0ka [10]
3 years ago
6

11/x^2+3x+2 and 1/x+2 find the lcd

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

(x + 1)(x + 2)

Step-by-step explanation:

Factorise the denominator of the first fraction

x² + 3x + 2 = (x + 1)(x + 2) ← in factored form

The denominator of each fraction must be able to divide into the lcd

Hence lcd is (x + 1)(x + 2)


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Step-by-step explanation:

Volume formula for cylinder is:

V=pi*r^2*h

V=pi*1*1

V=pi in^3

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What is the simplified form of 15 times x to the fifth power over 20 times y to the sixth power times the fraction 6 times y to
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The teachers at West Elementary are planning a field trip for 385 students. It will cost $1,750 for transportation and $3,080 fo
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5 0
3 years ago
A chemist whishes to prepare 100 liters of 45% purity of sulphuric acid .He has two kinds of acid solutions in stock ,one is 55%
tester [92]

Answer:

the chemist should use 60 liters of 55% solution and 40  litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.

Step-by-step explanation:

From the given information,

Let x be the litres of 55% pure solution

Let y be the litres of 30% pure solution

Also;

Given that our total volume of solution is  100 litres

x+y =100  ---- (1)

The total solution of pure by related by the sum of the individual pure concentrations to make up the concentration of final solution.

(0.55)(x)+(0.30)(y) = 0.45(100) ---- (2)

From equation (1)

Let ; y = 100 - x

Replacing the value for y = 100 - x into equation (2)

(0.55)(x)+(0.30)(100-x) = 0.45(100)

0.55x + 30 - 0.30x = 45

0.55x - 0.30x = 45 - 30

0.25x = 15

x = 15/0.25

x = 60 liters of 55% solution

From ; y = 100 - x

y = 100 - 60

y = 40  litres of 30% solution.

Therefore, the chemist should use 60 liters of 55% solution and 40  litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.

7 0
4 years ago
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