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Pie
3 years ago
10

Find the area_______​

Mathematics
1 answer:
Ray Of Light [21]3 years ago
6 0

Answer:

32√3

Step-by-step explanation:

area = product of diagonals/2

= (8√3 × 8)/2

= 64√3 /2

= 32√3

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ming-li be spent $15 at the movies. She then earned $30 babysitting. She spent$12 at the bookstore. She now has $18 left. How mu
MrMuchimi

Answer:

$15

Step-by-step explanation:

She began with $15.

3 0
3 years ago
Read 2 more answers
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
Plisss help on my assesment
Anon25 [30]

Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is <u>NOT</u> equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> <u>6x + 48</u>

Bring in the first expression ~ <u>6x+48 and 6x+48 </u>

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ <u>7x+21 and 10x + 6</u>

They are NOT the same, so they are NOT equivalent

6 0
3 years ago
Please help please please please
rodikova [14]
6
21.3
is the sum
5 0
3 years ago
What is a equivalent expression for 3y+y+4+y
kherson [118]

an equivalent expression is 5y+4

there is 3y which is y+y+y

so you have y+y+y+y+4+y

there are 5 y so it is 5y

then you have +4

5y+4

7 0
3 years ago
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