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yaroslaw [1]
3 years ago
13

Solve: 6 -0.2x = 2 (6 -0.6x)

Mathematics
1 answer:
Zolol [24]3 years ago
6 0
The answer is x=18

Explanation:

6-0.2x=2(6-0.6x)

+0.2. +0.2

6=12-x

+12. +12

18=x
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tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

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8 0
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Read 2 more answers
Naomi has 45 minutes to get ready for school she spends x minutes getting dressed write an expression that respetents the number
andriy [413]
ANSWER

(45  - x) \: minutes

EXPLANATION

Total minutes Naomi has at her disposal is 45 minutes.



The number of minutes she spends getting dressed is

x


To find the number of minutes she still has to get ready, we subtract the minutes spent from the total minutes.

The number of minutes she still have to get ready is

(45  - x) \: minutes

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