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Viktor [21]
3 years ago
5

Helppppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
Westkost [7]3 years ago
8 0
[2^(1/2)*(2^(3/4)]<span>^2</span>
the answer is  √2^5
Leviafan [203]3 years ago
7 0
Your answer is B if you were to simplify the expression you would get 4√2
You might be interested in
Review the following information about vectors q and r.
Vitek1552 [10]
<h3>Answer:  a = -1  (fourth choice)</h3>

==========================================

Work Shown:

q = (-4, 1) is one vector

r = (a,3) is another vector

The resultant vector is

q+r = (-4,1)+(a,3)

q+r = (-4+a,1+3)

q+r = (-4+a,4)

Multiply both sides by 7

7(q+r) = 7*(-4+a,4)

7(q+r) = (7*(-4+a),7*4)

7(q+r) = (-28+7a, 28)

---------------

Since 7(q+r) = (-35, 28), we know that,

(-28+7a, 28) =  (-35, 28)

which leads to

-28 + 7a = -35

when we equate the x components of each vector. Let's solve for 'a'

-28 + 7a = -35

7a = -35+28

7a = -7

a = -7/7

a = -1

--------------

Check:

q = (-4,1)

r = (a,3) = (-1,3)

q+r = (-4,1)+(-1,3)

q+r = (-4+(-1), 1+3)

q+r = (-5, 4)

7*(q+r) = 7*(-5, 4)

7*(q+r) = (7*(-5), 7*4)

7*(q+r) = (-35, 28)

The answer is confirmed.

7 0
2 years ago
Read 2 more answers
Y=4.76x what is the constant of proportionality
zalisa [80]

Answer:

4.76

Step-by-step explanation:

constant of proportionality=slope

slope=m

y=mx+b

m=4.76

4 0
3 years ago
How many positive integers can be expressed ad a product of two or more of the prime numbers 5,7,11,and 13 if no one product is
sertanlavr [38]

Answer:

11 positive integers can be expressed.

Step-by-step explanation:

Consider the provided information.

The number of possible prime numbers are 5,7,11,and 13.

There are 4 possible prime numbers.

How many positive integers can be expressed as a product of two or more of the prime numbers, that means there can be product of two numbers, three number or four numbers.

The formula to calculate combinations is: ^nC_r=\frac{n!}{r!(n-r)!}

The number of ways are:

^4C_2+^4C_3+^4C_4=\frac{4!}{2!(4-2)!}+\frac{4!}{3!(4-3)!}+\frac{4!}{4!}

^4C_2+^4C_3+^4C_4=\frac{4!}{2!2!}+\frac{4!}{3!}+1

^4C_2+^4C_3+^4C_4=6+4+1

^4C_2+^4C_3+^4C_4=11

Hence, 11 positive integers can be expressed.

8 0
3 years ago
Kaitlin, Hans, Eric went a total of 98 Text messages during the weekend. Kaitlin 68 more messages than Hans, Eric sent three tim
Phantasy [73]

Answer:

Hans:6

Eric:18

Kaitlin:74

Step-by-step explanation:

first create an equation using the information in the question

5h+68=98

first subtract  68

5h+68=98

    -68  -68

5h=30

divide by 5

Hans:6

multiply by 3

Eric:18

68+6=74

Kaitlin:74

Hope this helps! Plz award Brainliest : )

4 0
3 years ago
Read 2 more answers
ANSWER IS C
MA_775_DIABLO [31]

Answer:

x <2

Step-by-step explanation:

2.5 – 1.2x < 6.5 – 3.2x

Add 3.2x to each side

2.5 – 1.2x+3.2x < 6.5 – 3.2x+3.2x

2.5 +2x < 6.5

Subtract 2.5 from each side

2.5+2x-2.5<6.5-2.5

2x<4

Divide by 2

2x/2 < 4/2

x <2

8 0
2 years ago
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