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Reptile [31]
2 years ago
13

Solve the equation. a-6=13

Mathematics
2 answers:
Lunna [17]2 years ago
8 0
19 I hope this helps
mylen [45]2 years ago
8 0

Answer:

a=19

Step-by-step explanation:

In this equation you want to solve for a

In this case you simply add 6 to 13 because -6 is attached to the a on the left side and you want a on it's own.

a - 6 = 13  

+6       +6       (-6+6 = 0) (6+13=19)

a = 19

You might be interested in
An experiment was conducted to examine two different memorization methods to see which method allows people to remember better.
wlad13 [49]

Question Completion:

SubID  Memory1     Memory2

1                 71                78

2               75                75

3               77                82

4               90                91

5               72                90

6               79                 81

7               84                 75

8               75                 86

9               85                 92

10              75                 77

11               72                 92

12               76                87

13               77                93

14               90                94

15               84                78

16               73                92

17               75                85

18               87                86

19               75               95

20              70               94

21               72               75

22              90               84

23               81               94

24               87               82

25              90               82

26              87               79

27              78               94

28              78               79

29              70               82

30               81               80

31               80               78

32              90               87

33              83               90

34               81               85

35              73               88

36              82               82

37              84               94

38              85               86

39              77               94

40               82              83

Answer:

Since the mean of Memory1 (reciting method) (79.8) is smaller than the mean of Memory2 (imagery method) (85.5), we can conclude that there is a significant difference in memory performance between the reciting method and the imagery method.

Step-by-step explanation:

a) Data and Calculations:

SubID  Memory1     Memory2

1                 71                78

2               75                75

3               77                82

4               90                91

5               72               90

6               79                81

7               84                75

8               75                86

9               85                92

10              75                77

11               72                92

12              76               87

13              77               93

14              90               94

15              84               78

16              73               92

17              75               85

18              87               86

19              75               95

20             70               94

21              72               75

22             90               84

23              81               94

24             87               82

25            90               82

26             87               79

27             78               94

28             78               79

29             70               82

30              81               80

31              80               78

32             90               87

33             83               90

34              81               85

35             73               88

36             82               82

37             84               94

38             85               86

39             77               94

40             82               83

Total     3,193          3,421

Mean     79.8            85.5

Difference in means = 5.7 (85.5 - 79.8)

7 0
3 years ago
PLEASE HELP I GIVE BRAINLIEST AND POINTS! I GRINDED 4 THESE POINTS SO PLZ DONT PUT LINKS
Zolol [24]

Answer: It equals a

Step-by-step explanation:

5 0
3 years ago
A geometric sequence is shown on the graph below. What is the formula for the nth term of the sequence?
larisa [96]

Answer:

\boxed{u_n=40*(\frac{1}{2} )^{n-1})}\\

Step-by-step explanation:

u_1=40\\\\u_2=20=u_1*(\frac{1}{2} )^{2-1}\\\\u_3=10=u_1*(\frac{1}{2} )^{3-1}\\\\u_4=5=u_1*(\frac{1}{2} )^{4-1}\\\\u_5=2.5=u_1*(\frac{1}{2} )^{5-1}\\\\\\\boxed{u_n=40*(\frac{1}{2} )^{n-1})}\\

4 0
3 years ago
A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n
ki77a [65]

Answer:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0
3 years ago
Draw the image of △ABC under a dilation whose center is P and scale factor is 1/2.
Feliz [49]

Answer:

  See below

Step-by-step explanation:

Each point on the triangle moves to half its previous distance from P.

3 0
4 years ago
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