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3 years ago

8^(c+1)=16^(2c+3) solve the inequality please show work

Mathematics

1 answer:

tresset_1 [31]3 years ago

4 0

Answer:

Step-by-step explanation:

$8^{c+1}=16^{2c+3}\\(2^{3} )^{c+1} =(2^{4}) ^{2c+3} \\2^{3(c+1)} =2^{4(2c+3)} \\3(c+1)=4(2c+3)\\3c+3=8c+12\\8c-3c=3-12\\5c=-9\\c=-\frac{9}{5}$

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6.02 QUIZ COMPARE EXPRESSTIONS

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C is the right answer

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Simplify to create an equivalent expression. 10+4(-8 q-4)}10+4(−8 q−4)

ale4655 [162]

Answer:: -0.3125 + q + 0.5

If our equation is: 10 + 4(-8q - 4) then we can simplify it in the next way:

first distribute the 4 with the content in the parentheses.

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A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

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4 years ago

Please help will mark brainlyist and 10 points if right

Anit [1.1K]

Answer:

can u copy the text and send it to help u

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3 years ago