3 years ago

8^(c+1)=16^(2c+3) solve the inequality please show work

Mathematics

1 answer:

tresset_1 [31]3 years ago

4 0

Answer:

Step-by-step explanation:

$8^{c+1}=16^{2c+3}\\(2^{3} )^{c+1} =(2^{4}) ^{2c+3} \\2^{3(c+1)} =2^{4(2c+3)} \\3(c+1)=4(2c+3)\\3c+3=8c+12\\8c-3c=3-12\\5c=-9\\c=-\frac{9}{5}$

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