Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
x=-5, y=-8. (-5, -8).
Step-by-step explanation:
-x+2y=-11
5x-8y=39
---------------
5(-x+2y)=5(-11)
5x-8y=39
---------------------
-5x+10y=-55
5x-8y=39
--------------------
2y=-16
y=-16/2
y=-8
-x+2(-8)=-11
-x-16=-11
-x=-11+16
-x=5
x=-5
Answer:
8xb + 456x
Step-by-step explanation:
8x(b + 456)
8xb + 456x
You multiply 8x by the numbers in the parenthesis. And you add the variables to the coefficents.
<em>I hope it helps! Have a great day!</em>
<em>Lilac~</em>
Answer:
Its C i think
Step-by-step explanation: