We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2
the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14
</span>
MUSTARD MAN
1) 16y+0=0 Identity Property Of Addition
2) d*r=r*d Commutive property of multiplication
3) 27a*0=0 Identity Property of Addition
4) 16x+5y=5y+16x Commutive property of Addition
5) r*1=r Identity property of Addition
6) (5y+2)+14x=5y+(2+14x) Associate property of Addition
7) (m*n)*p=m*(n*p) Associate Property of Multiplication
Please use the information you have to make sure these are RIGHT!!!!
-GENERAL OUT
Or use photomath, it is also useful!
The sum that represents the number of tickets sold if 35 tickets were sold Monday, half of the remaining tickets were sold on Tuesday and 14 tickets were sold on Wednesday.
To start solving this, we can assign t as the variable to the total number of tickets that were sold. So, t = 35 (for Monday) + (t - 35)/2 (for Tuesday) + 14 (for Wednesday). To solve this, we can say t = 49 + (t - 35)/2, or 2t = 98 + t - 35, which equals t = 63. Therefore, 63 tickets were sold total.
Answer:
(![\sqrt[5]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D)
)^7
Step-by-step explanation:
to cancel out the radical you do the exponent inside and divide it by the out side one so it will be 7/5 so make it x to the expontent of 7/5 and to do rational exponets it will be (^5radicalx)^7
