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3 years ago

I literally have no clue what this unit is about so help

Mathematics

2 answers:

vaieri [72.5K]3 years ago

5 0

The answer is D
if the legs are 5 and 4 cm the equation to find the hypotenuse would be 5^2+4^2=c^c
5 squared is 25 and 4 squared is 16 that gives you 41, normally you would square root the 41 but it gives you a decimal number

kaheart [24]3 years ago

3 0

Answer:

4) √41 cm
5) 8 cm or √514 cm

Step-by-step explanation:

According to Pythagorean:

c² = a² + b²
c² = 4² + 5² = 16 + 25 = 41
c = √41

Two sides are 15 cm and 17 cm

If the third side is hypotenuse, its length is:

c = √(15² + 17²) = √514 cm

If the third side is leg, its length is:

a = √(17² - 15²) = √64 = 8 cm

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Write the equation of a line that is perpendicular to the line y= - 1/3x +8 and passes through the point (0,-4)

pantera1 [17]

The answer would be y = 3x-4

8 0

3 years ago

Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the

maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

$y=ax^2+bx+c$

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

$x_v=-\frac{b}{2a}$

In this problem, we have:

$y=-x^2-6x-13$

Then:

a = -1

b = -6

We write now:

$x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3$

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

$-x^2-6x-13=0$

To solve this, we can use the quadratic formula:

$x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}$

And solve:

$x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}$ $x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}$

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

$y=-0^2-6\cdot0-13=-13$

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

$x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20$ $x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8$

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

$y=-(-3)^2-6(-3)-13=-9+18-13=-4$

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0

1 year ago

Find the solution of the system by graphing

zvonat [6]

Answer:

x = -2

y = -1

(-2, -1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination
Solving systems of equations by graphing

Step-by-step explanation:

Step 1: Define systems

y = x + 1

3x + 3y = -9

Step 2: Solve for x

Substitution

Substitute in y: 3x + 3(x + 1) = -9
Distribute 3: 3x + 3x + 3 = -9
Combine like terms: 6x + 3 = -9
Isolate x term: 6x = -12
Isolate x: x = -2

Step 3: Solve for y

Define original equation: y = x + 1
Substitute in x: y = -2 + 1
Add: y = -1

Step 4: Graph systems

Check the solution set.

6 0

3 years ago

The quotient of 36 and 3 is j. write expression

Dovator [93]

This might be a mistake but i'll give it a go:

36/3 = j

4 0

3 years ago

Read 2 more answers

100 points and I will mark brainliest to bc I just want to be nice

olga2289 [7]

Answer:

is there a question?

Step-by-step explanation:

3 0

2 years ago