Write an equation.
T = Total money made
M = miles driven
4 + 2.25m
T = 7.3*2.25 + 4 + 2.25*4.8 + 4
T = 8 + 7.3*2.25 + 2.25 * 4.8
4.8 * 2.25 = 10.8
7.3 * 2.25 = 16.425
T = 16.425 + 8 + 10.8
T = 35.225
So, the total amount of money he made was $35.25.
Answer:
Number of years between 1950 and 2100 =

150 = 50 + 50 + 50 years.

So, total population in 2100 is 375,000,000.
Answer: 
Step-by-step explanation:






Answer:
8.27 ft.
Step-by-step explanation:
Using trigonometry of a right angled triangle:
cos 74 = x / 30 where x is the required distance
x = 30 cos 74
= 8.269 ft