Answer:
The change in the area of the rectangle is 0 square feet
Step-by-step explanation:
To solve this problem we have to calculate the area of the two rectangles that give us
first we have to know the formula to calculate the area of a rectangle
a = area
l = length = 12ft
w = width = 5ft
a = l * w
we replace the known walues
a = 12ft * 5ft
a = 60ft²
we do the same with the other rectangle, but first we have to calculate its sides
w = 5ft - (5ft * 20/100)
w = 5ft - 1ft
w = 4ft
l = 12ft + (12ft * 25/100)
l = 12ft + 3ft
l = 15ft
a2 = 15ft * 4ft
a2 = 60ft²
to calculate the change in the area we subtract (a - a2)
a - a2 =
60ft² - 60ft² = 0ft²
Answer:
1/6
Step-by-step explanation:
there are 6 faces on a die if you a roll a die the chance of getting a 2 or 5 is 1/6
Answer:
C
15 + x
Step by step explanation
For Company X, the initial cost is 30 cents plus 5 cents per minute, so the expression would be 30 + 5x (x would represent minutes.
For Company Y, the initial cost is 15 cents plus 4 cents per minute, so the expression would be 15 + 4x (x would represent minutes.)
Then subtract the expression of Y from the expression of X to show the difference in value between Y and X.
So, 30 + 5x - (15 +4x)
Distribute the subtraction sign.
30 + 5x - 15 - 4x
Solve across.
15 + x
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
![=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha](https://tex.z-dn.net/?f=%3DL%5Ctimes%20B%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height%5C%5C%5C%5C%3D%5B1500%5Ctimes%20%285000-2000-1500%29%5D%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%283000-1500%29%5Ctimes%20%285000-2000-1500%29%5C%5C%5C%5C%3D3375000m%5E2%3D337.5ha)
Area of region 2 = ar(DHBC)

Area of region 3 = ar(GFEH)

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Answer:
The value of x is 5
Step-by-step explanation:
In the given triangle
∵ A segment joining two points lie on the two side
∵ This segment is parallel to the third side
∴ This segment divides the two sides into parts that have the same ratio
→ That means x over 2x - 3 equal to 10 over 14
∵
= 
→ By using cross multiplication
∴ 10 × (2x - 3) = x × 14
∴ 10(2x) - 10(3) = 14x
∴ 20x - 30 = 14x
→ Add 30 to both sides
∵ 20x - 30 + 30 = 14x + 30
∴ 20x = 14x + 30
→ Subtract 14x from both sides
∵ 20x - 14x = 14x - 14x + 30
∴ 6x = 30
→ Divide both sides by 6
∴ x = 5
∴ The value of x is 5