We want to find the distance between the first page of the first book in a collection and the last page of that collection.
We will get that the distance is 13cm
Let's see how to solve this:
<u>We know that:</u>
- Each cover is 0.5cm thick
- The pages (all of them) for each volume are 5cm thick.
We want to find the distance between the first page of the first volume and the last page of the last volume.
Because we go from the first page of the first volume to the last page of the last volume, we <u>will ignore the first cover and pages of the first volume and the pages and back cover of the last volume</u>.
We ignore the pages because in normal book positioning, the first page will be on the right side of the book (and the last page is on the left side), and if we order the books from left to right, then we can ignore all the other pages of book I and book IV.
Then we have:
- one cover for volume 1.
- two covers and pages for volume 2
- two covers and pages for volume 3
- one cover for volume 4.
Now we just need to add all the correspondent measures:
( 0.5cm) + (5cm + 2*0.5cm) + (5cm + 2*0.5cm) + ( 0.5cm) = 13cm
Then the distance between the page 1 of volume I and last page of volume IV is 13cm.
If you want to learn more, you can read:
brainly.com/question/12082741
"interverted" or "inverted?"
The vertical height of an inverted cone with base diameter 6 cm and slant height of 6 cm can be found using the Pyth. Thm. Draw or imagine a triangle whose height is h and whose base is 3 cm (not 6) and whose hypotenuse is 6 cm.
Then h^2 + (3 cm)^2 = (6 cm)^2, or h^2 + 9 cm^2 = 36 cm^2, or h^2 = 27 cm^2.
Then the height of the triangle, as well as of the cone, is h = +√27, or
h = +3√3.
Answer: 
Step-by-step explanation:
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X 4
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C and d this is the answer to everthing in life
Answer:
7 seconds
Step-by-step explanation:
y=-16t²+96t+112, where t is time and y is distance above water.
We are looking for t when y=0
-16t²+96t+112=0
t²-6t-7=0
(t-7)(t+1)=0
Either t=7 or t=-1.
Since we cant have negative time, the answer is t=7
