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2 years ago

Solve the following equation (x-4)^2=7

2 answers:

7 0

$(x-4)^2 =7\\\\\implies x-4 = \pm \sqrt 7\\\\\implies x = 4 \pm \sqrt 7\\\\\ \text{Hence,}~ x =4 + \sqrt 7~~ \text{or}~~x =4 -\sqrt 7$

melomori [17]2 years ago

5 0

$(x-4) ^ 2 = 7 => | x-4 | = \sqrt{7} \\=> x-4=\sqrt{7} / or/ x-4=-\sqrt{7}\\ => x=\sqrt{7} + 4 /or/ x = 4-\sqrt{7}$

ok done. Thank to me :>

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adelina 88 [10]

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3 years ago

What are the potential solutions of In(x^2-25)=0?

Maslowich

Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

Given :-

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

Equation :-

$\implies log_e {(x^2-25)}= 0$

In general :-

If we have a logarithmic equation as ,

$\implies log_a b = c$

Then this can be written as ,

$\implies a^c = b$

In a similar way we can write the given equation as ,

$\implies e^0 = x^2 - 25$

Now also we know that $a^0 = 1$ Therefore , the equation becomes ,

$\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}$

Hence the Solution of the given equation is ±√26.

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3 years ago

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Softa [21]

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3 years ago

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Lemur [1.5K]

Answer: Yes

Step-by-step explanation:

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3 years ago

Read 2 more answers

The diameter of the base of the cone measures 8 units. The height measures 6 units

daser333 [38]

For this case we can find the volume and area of the cone:

$V = \frac {\pi * r ^ 2 * h} {3}$

Where:

V: It's the volume

A: It's the radius of the base

h: It's the height

We have to:

$r = \frac {8} {2} = 4 \ units\\h = 6 \ units$

Substituting:

$V = \frac {\pi * 4 ^ 2 * 6} {3}\\V = \frac {96 * \pi} {3}\\V = 32 \pi \ units ^ 3$

On the other hand, the area of the cone is given by:

$A = \pi * r * g + \pi * r ^ 2$

Where:

A: It's the radio

g: It is the generator of the cone.

$g = \sqrt {h ^ 2 + r ^ 2} = \sqrt {6 ^ 2 + 4 ^ 2} = \sqrt {36 + 16} = \sqrt {52} = 7.2$

SW:

$A = \pi * 4 * 7.2 + \pi * 4 ^ 2\\A = 28.8 \pi + 16 \pi\\A = 44.8 \pi \ units ^ 2$

Answer:

$V = 32 \pi \ units ^ 3\\A = 44.8 \pi \ units ^ 2$

7 0

3 years ago