Question

Solve the following equation (x-4)^2=7

Answer 1

$(x-4)^2 =7\\\\\implies x-4 = \pm \sqrt 7\\\\\implies x = 4 \pm \sqrt 7\\\\\ \text{Hence,}~ x =4 + \sqrt 7~~ \text{or}~~x =4 -\sqrt 7$

Answer 2

$(x-4) ^ 2 = 7 => | x-4 | = \sqrt{7} \\=> x-4=\sqrt{7} / or/ x-4=-\sqrt{7}\\ => x=\sqrt{7} + 4 /or/ x = 4-\sqrt{7}$

ok done. Thank to me :>