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seropon [69]
3 years ago
5

Find the value of x in the equation below. x+1=6

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0
X+1=6
Move the constant to the right hand side and change its sing
X=6-1
You subtract the number
X=5
And that’s your solution
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Help me pllzzz explain how this is solved theres an answer but idk how u get it
MrMuchimi
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What is 5 with eponenet of 2
kondaur [170]

Answer:

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=32

Step-by-step explanation:

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Arianna runs up 4 flights of stairs and then runs down 4 flights of stairs. Does this situation represent additive inverses?Expl
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4 0
3 years ago
Please can anyone send a question in law of indices I really need it now​
DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

(9^p)(27^q)=3^n\\

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

(9^p)(27^q)=3^n\\\\

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

(3^2)^p(3^3)^q=3^n\\

now we multiply p with 2 and

multiply q with 3 respectively,

(3^{2p})(3^{3q})=3^n\\

now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base

3^{2p+3q}=3^n\\

now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,

2p+3q=n\\

hence n is expressed in terms of p and q

Solution to part b)

if p = 1 and q = 2 we plug in these values in the above equation we found for n

n = 2p + 3q

n = 2(1) + 3(2)

n = 2 + 6

n = 7

6 0
3 years ago
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