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ruslelena [56]
3 years ago
6

In three more years Miguel's grandfather will be six times as old as Miguel was last year. When Miguel's grandfather present age

is added to his grandfathers age is added to his grandfathers present age the total is 68. How old is his grandfather now ?
Mathematics
1 answer:
lora16 [44]3 years ago
7 0
"In three more years,Miguel's grandfather will be six times as old as Miguel was last year. When Miguel's present age is added to his grandfather's present age, the total is 68. How old is each one now?"

Miguel is 11 years old and his grandfather is 57 years old.
Last year Miguel was 10. In three more years his grandfather would be 60. 60/6=10. 11+57=68


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Jason eats 10 ounces of candy in 5 days. a. How many pounds does he eat per day?
Nadusha1986 [10]
A. He eats 1/8 a pound of candy each day.
B. It would take him a total of 8 days to eat a pound of candy.

A. Since he ate 10 ounces in 5 days, you divide 10 by 5 to find he ate 2 ounces per day. Since there are 16 ounces in a pound that would be your denominator (bottom of fraction) and 2 would be the numerator (top of your fraction). You will get 2/16 which if you simplify (divide by 2) you get 1/8.

B. Knowing that there are 16 ounces per pound and he ate 1/8 pound ( 2/16 pound or 2 ounces) a day, you can either look at the simplified denominator to get the answer, or, divide 16 by 2 to get your answer.

I hope this helps!
8 0
3 years ago
The manager of an apartment building increases the monthly
N76 [4]

Answer:

The answer is 513

6 0
4 years ago
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what is the solution to the system of equations: x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10
ladessa [460]

Given equations are x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10 .

It seems you have missed to write = in the 2nd equation so i have fixed the sign and going to solve the following system of equations:

x-y-z=2 ...(i)

-x-3y-2z=4 ...(ii)

-x-2z=10 ...(iii)


solve (i) for x

x=2+y+z ...(iv)

plug (iv) into (ii)

-x-3y-2z=4

-(2+y+z)-3y-2z=4

-2-y-z-3y-2z=4

-2-4y-3z=4

-4y-3z=6...(v)


plug (iv) into (iii)

-x-2z=10

-(2+y+z)-2z=10

-2-y-z-2z=10

-2-y-3z=10

-y=12+3z

y=-12-3z...(vi)


plug (vi) into (v)

-4y-3z=6

-4(-12-3z)-3z=6

48+12z-3z=6

48+9z=6

9z=-42

z=-14/3


Now plug value of z into (vi)

y=-12-3z=-12-3(-14/3)=-12+14=2

y=2


plug value of y and z into (iv)

x=2+y+z=2+2-14/3=-2/3


Hence final answer is x=-2/3, y=2, z=-14/3

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It's easier to see it as 80/100 or 8/10

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