Answer:
58%
Step-by-step explanation:
This is a problem of conditional probability.
Let A represent the event that student has dark hair.
So P(A) = 55% = 0.55
Let B represents the event that student has blue eyes.
So, P(B) = 60% = 0.60
Probability that student has blue eyes and dark hairs = P(A and B) = 35% = 0.35
We are to find the probability that a randomly selected student will have dark hair, given that the student has blue eyes. Using the given formula and values, we get:

Therefore, there is 0.58 or 58% probability that the student will have dark hairs, given that the student has blue eyes.
Answer:
22,440
Step-by-step explanation:
204 = 2 * 2 * 3 * 17
1320 = 2 * 2 * 2 * 3 * 5 * 11
They both have 2 2's and a 3 in common, so use them once
2 * 2 * 3 * 17 * 2 * 5 * 11 = 22,440
Answer:
4.12 kg
Step-by-step explanation:
Regular cakes:
1 dozen normal sponge cakes: 264 g plain flour
Vegetarian cakes:
1 dozen cakes: 264 g plain flour
4 eggs are replaced by 4 * 30 g of flour = 120 g flour
total flour for 1 dozen vegetarian cakes = 264 g + 120 g = 384 g
Proportion for regular cakes:
12 cakes to 264 g flour = 100 cakes to x grams flour
12/264 = 100/x
12x = 26400
x = 2200
2200 g flour for 100 regular cakes
Proportion for vegetarian cakes:
12 cakes to 384 g flour = 60 cakes to y grams flour
12/384 = 60/y
12y = 384 * 60
12y = 23040
y = 1920
1920 g flour for 60 vegetarian cakes
Total flour needed:
2200 g + 1920 g = 4120 g
4120 g * 1 kg/(1000 g) = 4.12 kg
Answer: 4.12 kg
Remainder of question:
Find the probability distribution of x
Answer:
The random variable x is defined as: X = {0, 1, 2, 3, 4}
The probability distribution of X:
P(X = 0) = 0.656
P(X = 1) = 0.2916
P(X= 2) = 0.0486
P(X=3) = 0.0036
P(X = 4) = 0.0001
Step-by-step explanation:
Sample size, n = 4
Random variable, X = {0, 1, 2, 3, 4}
10% (0.1) of the homeowners are insured against earthquake, p = 0.1
Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1
q = 0.9
Probability distribution of x,
Step-by-step explanation:
Total bulbs = 80
Probability of defective bulbs = 45/80 = 9/16
Probability of non warranty bulbs = 32/80 = 4/5