Answer:
6
how:
add up all the numbers the divide by the amount of numbers given.
Use:
First, I added all the numbers up and got 48.
Next, I divided by 8.
Last, I did 42 divided by 8 and got 6.
The mean is 6.
Answer:
0.966
Step-by-step explanation:
Given that:
Probability of DVD player breaking down before the warranty expires = 0.034
To find:
The probability that the player will not break down before the warranty expires = ?
Solution:
Here, The two events are:
1. The DVD player breaks down before the warranty gets expired.
2. The DVD player breaks down after the warranty gets expired
In other words, the 2nd event can be stated as:
The DVD does not break down before the warranty gets expired.
The two events here, have nothing in common i.e. they are mutually exclusive events.
So, Sum of their probabilities will be equal to 1.
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
