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KIM [24]
3 years ago
14

What is the slope for number 4?

Mathematics
1 answer:
Anton [14]3 years ago
4 0

Answer: -10/7

Step-by-step explanation:

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The equation y=my+b is the slope- intercept form of a linear equation solve y=mc+b for m
SVEN [57.7K]

We need to leave m alone on the right hand side, so let's move everything else to the left hand side.

First of all, we can subtract b from both sides to get

y-b = mc

Now, we can divide both sides by c to get

\dfrac{y-b}{c}=m

And so we solved the expression for m, because we have written an expression in the form m=\ldots, where the right hand side doesn't depend on m.

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3 years ago
What is 5 1/4 . 1 5/9 ? Express the answer in simplest form
Agata [3.3K]
5\dfrac{1}{4}\cdot1\dfrac{5}{9}=\dfrac{5\cdot4+1}{4}\cdot\dfrac{1\cdot9+5}{9}=\dfrac{21}{4}\cdot\dfrac{14}{9}=\dfrac{7}{2}\cdot\dfrac{7}{3}\\\\=\dfrac{7\cdot7}{2\cdot3}=\dfrac{49}{6}=\dfrac{48+1}{6}=\boxed{8\dfrac{1}{6}}
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3 years ago
What is the answer to this
photoshop1234 [79]

Answer:

true

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation
rodikova [14]

Answer: C) y=sin^-1 x

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point (1,\frac{\pi}{2}),

If this point satisfies the function,

For the function y=cos^{-1} x

If x = 1

y=cos^{-1}1=0

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=cos^{-1} x is not passing through the point  (1,\frac{\pi}{2})

For the function y=cot^{-1}x

If x = 1

y=cot^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function y=cot^{-1}x,

⇒ The graph of   y=cot^{-1}x is not passing through the point  (1,\frac{\pi}{2})

For the function y=sin^{-1} x

If x = 1

y=sin^{-1}1=\frac{\pi}{2}

Thus,  (1,\frac{\pi}{2}) is satisfying function y=sin^{-1} x,

⇒ The graph of   y=sin^{-1} x is passing through the point  (1,\frac{\pi}{2}).

For the function y=tan^{-1}x

If x = 1

y=tan^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=tan^{-1} x is not passing through the point (1,\frac{\pi}{2}).

Hence, Option C is correct.

3 0
3 years ago
What is the value of x in this triangle?
Dvinal [7]
X=10 the two triangles are the same size just one is scaled down by 1/2. Hope this helps
8 0
3 years ago
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