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Anarel [89]
3 years ago
15

21.6% of all registered doctors were female, if there were 45,200 females registered doctors that year, what was the total numbe

r of registered doctors? Round your answer to the nearest whole number
Mathematics
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

209259

Step-by-step explanation:

45200 / 21.6 = 209259.259259

209259.259259 rounded to nearest whole number = 209259

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Choose the appropriate descriptor for the term gram per centimeter cubed .
Oxana [17]

Answer:

Density

Step-by-step explanation:

The gram per centimeter cubed is a unit of density in the CGS system, normally used in chemistry, defined as mass in grams divided by volume in cubic centimeters. The official SI symbols are g/cm3, g·cm−3, or g cm−3.

6 0
4 years ago
Is absolute value of -998​
Nikitich [7]

Answer:

998.

Step-by-step explanation:

Just get rid of the negative sign

7 0
3 years ago
Read 2 more answers
You roll a six-sided number cube. What is the proability that you will roll a number greater than two.
koban [17]

Answer:

4/6 = 2/3

Step-by-step explanation:

Because, the question that is stated only asks for the probability that is greater than 2 so I think you should not include the 2. So the numbers would be 3,4,5,6.  Since it is a 6 sided cube, you would have 4 /6 which simplifies to 2/3

6 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
Solve the problem below.<br><br><br><br> 57°<br><br> 123°<br><br> 114°<br><br> 66°
grandymaker [24]

Answer:

66

Step-by-step explanation:

5 0
4 years ago
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