Answer:
Computer hardware engineer
Systems analyst
Database administrator
Companies often engage the services of Advertising firms to market their products. Company web offerings can be tailor-made for the consumers.
- Advertising agencies are firms that makes, plan and handle the advertising needs of any business. They are known for handling negotiations creating tailored marketing campaigns.
A lot of agencies do not want to talk about pricing until they know what you can afford to spend.
Tailored content are delivered experiences that speak directly to customers.
This agencies uses their connections and resources to make one's campaign successful and cost-efficient.
Learn more from
brainly.com/question/23477855
Answer:
Following are code that we fill in the given in the given question
if i %2==0:# check the condition
new_list.append(elements[i])# append the list
return new_list # return the new_list
Explanation:
Missing Information :
def skip_elements(elements):# function
new_list=[]# Declared the new list
i=0 #variable declaration
for i in range(len(elements)): #iterating over the loop
if ---------# filtering out even places elements in the list
--------------# appending the list
return -------- # returning the new_list
print(skip_elements(['a','b','c','d','e','f','g'])) #display
Following are the description of the code:
- In this we declared a function skip_elements .In this function we pass the parameter into them .
- After that we declared the new_list array.
- Declared the variable "i" that are initialized with the 0 value .
- Iterating over the for loop and this loop we check the condition in the if condition.
- The if condition executed when the index is even .The statement inside the if condition we will appending the list and returning the list item .
- Finally we print the even number of index list .
Contact them. Call them and explain the issue.
Answer:
64 terabytes
Explanation:
Given data:
Size of the disk block = 8 KB
Size required by the pointer to a disk block = 4 bytes
Now,
Size required by 12 direct disk blocks = 12 × 8
Size required by single disk block = 2048 × 8 KB
Size required by double disk block = 2048 × 2048 × 8 KB
size required by triple disk block = 2048 × 2048 × 2048 × 8 KB
Now,
the maximum size of the file that can be stored in the this file system = 12 × 8 + 2048 × 8 KB + 2048 × 2048 × 8 KB + 2048 × 2048 × 2048 × 8 KB = 64 terabytes
