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1 year ago

30 POINTS FOR THE ANSWER

Computers and Technology

1 answer:

vladimir2022 [97]1 year ago

4 0

The possible solutions are:

Ask for a printed or click on proof to get the right color match.
One can use Pantone colors as it aids with color matching.

<h3>How do one do the above?</h3>

Computers is known to often use the same data and it often uses it to bring up clarity or light up pixels on its screen.

Therefore to get the result above, one need to check system preference system setting to get different brightness and color settings.

Therefore, The possible solutions are:

Ask for a printed or click on proof to get the right color match.
One can use Pantone colors as it aids with color matching.

Learn more about printed colors from

brainly.com/question/1548113

#SPJ1

You might be interested in

What happens when you create a variable in a video game program?

gulaghasi [49]

Answer:

A lot can happen, depending on the use of the variable

Explanation:

Lets create a position variable, a common variable in games.

Vector3 position = new Vector3(0, 0, 0);

The above variable initialization creates a new Vector3 object. The Vector3 class contains 3 properties, X, Y, and Z. When you assign the variable 'position' the new Vector3 object, the variable 'position' contains an instance of Vector3 where

X = 0,

Y = 0,

and Z = 0.

The variable 'position' can be used to set the position of a player, or an object.

We can reuse this variable when you want the object or player to move.

position.X = 29

position.Y = -14

position.Z = 47

now the object/player's position is (29, -14, 47).

Variables can be used for basically everything you need in programming, from storing a position, to storing the result of a complex math equation.

7 0

2 years ago

Which three pieces of information should be included in an artist statement? Select all that apply.

Dima020 [189]

Answer:

There is no answers given??

Explanation:

N/A

4 0

2 years ago

A technician receives an invalid certificate error when visiting a website with port 443 enabled. Other computers on the same LA

amm1812

Answer:

Option (A) is the right answer.

Explanation:

According to the scenario, the user system is giving the error of invalid certificate while other users on the same network do not report any error, which means that there is some problem in a particular system.

Date and time can also be one of the main cause of this error because wrong date and time creates problem in surfing many websites by giving certificate error.

Hence the most appropriate answer is option (A).

While other option are wrong because of the following reasons:

UEFI boot mode is mainly used in booting the operating system and has no connection with network.

Logon time is also wrong because if the problem is with the login server, it can not give certificate error.

User access control is also not correct because it is used to control the access of the user.

7 0

3 years ago

Match the technology with the appropriate task.

Fiesta28 [93]

Answer:

the number order is

Explanation:

I am sure it is correct. Thanks :)

3 0

3 years ago

[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri

AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name -> Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 ( Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name -> Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 ( Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ). with candidate keys Course_Name and Course_ID.

6 0

3 years ago