Answer:
def typeHistogram(it,n):
d = dict()
for i in it:
n -=1
if n>=0:
if str(type(i).__name__) not in d.keys():
d.setdefault(type(i).__name__,1)
else:
d[str(type(i).__name__)] += 1
else:
break
return list(d.items())
it = iter([1,2,'a','b','c',4,5])
print(typeHistogram(it,7))
Explanation:
- Create a typeHistogram function that has 2 parameters namely "it" and "n" where "it" is an iterator used to represent a sequence of values of different types while "n" is the total number of elements in the sequence.
- Initialize an empty dictionary and loop through the iterator "it".
- Check if n is greater than 0 and current string is not present in the dictionary, then set default type as 1 otherwise increment by 1.
- At the end return the list of items.
- Finally initialize the iterator and display the histogram by calling the typeHistogram.
The principle or element of layout design is highlighted in an event poster in option i: The headline.
<h3>What are the elements of page layout?</h3>
The poster is known to be one that often uses a kind of hierarchy and centered text alignment as its element.
Note that it is one whose Lines of use is said to be made up of different kinds of type styles, sizes and others.
The simple elements of an advertising poster is made up of:
1. The headline.
2. The sub-head.
3. The body copy.
4. The caption.
The elements of page layout are visual hierarchy, visual flow, and others. Hence, the principle or element of layout design is highlighted in an event poster in option i: The headline.
Learn more about layout design from
brainly.com/question/2501083
#SPJ1
Answer:
An observation: Java does not support true multi-dimensional arrays; rather, it supports 1-dimensional arrays, where each element can itself be another 1-dimensional array. The difference is the way memory is allocated, where a[i][j] differs from a[i,j].
Explanation:
Answer:
Following are the code to this question:
#include <iostream> //defining header file
using namespace std;
void numbers(ostream &outs, const string& prefix, unsigned int levels); // method declaration
void numbers(ostream &outs, const string& prefix, unsigned int levels) //defining method number
{
string s; //defining string variable
if(levels == 0) //defining condition statement that check levels value is equal to 0
{
outs << prefix << endl; //use value
}
else //define else part
{
for(char c = '1'; c <= '9'; c++) //define loop that calls numbers method
{
s = prefix + c + '.'; // holding value in s variable
numbers(outs, s, levels-1); //call method numbers
}
}
}
int main() //defining main method
{
numbers(cout, "THERBLIG", 2); //call method numbers method that accepts value
return 0;
}
Output:
please find the attachment.
Explanation:
Program description:
- In the given program, a method number is declared, that accepts three arguments in its parameter that are "outs, prefix, levels", and all the variable uses the address operator to hold its value.
- Inside the method a conditional statement is used in which string variable s and a conditional statement is used, in if the block it checks level variable value is equal to 0. if it is false it will go to else block that uses the loop to call method.
- In the main method we call the number method and pass the value in its parameter.
