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Alexxandr [17]
2 years ago
7

An amusement park has two themed resorts, Stargazer Suites and Retro Retreat. The graph and table below display the cost of the

stay, y, for different numbers of nights, x, for the two different resorts.
Which statement correctly compares the nightly rates at Stargazer Suites and Retro Retreat?

The nightly rate at Stargazer Suites is $15 more than the nightly rate at Retro Retreat.

The nightly rate at Stargazer Suites is $25 more than the nightly rate at Retro Retreat.

The nightly rate at Retro Retreat is $30 more than the nightly rate at Stargazer Suites.

The nightly rate at Retro Retreat is $80 more than the nightly rate at Stargazer Suites.

The nightly rate at each resort is the same.
Mathematics
1 answer:
tekilochka [14]2 years ago
4 0

Answer:

to confusing

Step-by-step explanation:

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1/2x+1/3y=5 and 1/4x+y=10 solve this system by substitution
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Answer:

  (x, y) = (4, 9)

Step-by-step explanation:

You can use the second equation to write an expression for y.

  y = 10 - 1/4x . . . . subtract 1/4x from the given 2nd equation

Now, substitute that for y in the first equation:

  1/2x + 1/3(10 -1/4x) = 5

  1/2x + 10/3 -1/12x = 5 . . . . eliminate parentheses

You can work this a couple of ways from here. One is to multiply by 12 to eliminate fractions. Another is to work with the numbers as they are. We'll do that, because we don't get enough practice doing arithmetic with fractions.

  5/12x = 5/3 . . . . . subtract 10/3

  x = (5/3)/(5/12) = 12/3 = 4

From above, we can use our expression for y:

  y = 10 - 1/4·4 = 9

The solution is (x, y) = (4, 9).

 

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The radius of a face-off circle on an NHL hockey<br>rink is 15 ft. What is its circumference?​
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Answer:

94.2ft

Step-by-step explanation:

  1. The formula for finding the circumstance is the diameter times pi.
  2. We know the radius. To find the diameter, we double the radius, which would be 30. (2x15=30)
  3. Next, we multiply 30 by pi. (30x3.14). The answer is 94.2.
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\huge \boxed{\mathfrak{Question} \downarrow}

  • Expand & simplify ⇨ ( \sqrt{10}  -  \sqrt{2} ) ^{2}. Give your answer in the form b - c \:  \sqrt{5} where b & c are integers.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

( \sqrt { 10 } - \sqrt { 2 } ) ^ { 2 }

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{10}-\sqrt{2}\right)^{2}.

\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}

The square of \sqrt{10} is 10.

10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}

Factor 10=2\times 5. Rewrite the square root of the product \sqrt{2\times 5} as the product of square roots \sqrt{2}\sqrt{5}.

10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}

Multiply \sqrt{2} and \sqrt{2} to get 2.

10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}

Multiply -2 and 2 to get -4.

10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}

The square of \sqrt{2} is 2.

10-4\sqrt{5}+2

Add 10 and 2 to get 12.

\boxed{ \boxed{\bf\:12-4\sqrt{5} }}

  • Here, b & c are integers where \boxed{ \sf \: b = 12 \: and \: c = 4}
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3 years ago
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